x^4/3-7x^2/3-10=0

Solution for x^4/3-7x^2/3-10=0 equation:

x in (-oo:+oo)

(x^4)/3-((7*x^2)/3)-10 = 0

(x^4)/3+(-7/3)*x^2-10 = 0

1/3*x^4-7/3*x^2-10 = 0

t_1 = x^2

1/3*t_1^2-7/3*t_1^1-10 = 0

1/3*t_1^2-7/3*t_1-10 = 0

DELTA = (-7/3)^2-(-10*1/3*4)

DELTA = 169/9

DELTA > 0

t_1 = ((169/9)^(1/2)+7/3)/(1/3*2) or t_1 = (7/3-(169/9)^(1/2))/(1/3*2)

t_1 = 10 or t_1 = -3

t_1 = -3

x^2+3 = 0

1*x^2 = -3 // : 1

x^2 = -3

t_1 = 10

x^2-10 = 0

1*x^2 = 10 // : 1

x^2 = 10

x^2 = 10 // ^ 1/2

abs(x) = 10^(1/2)

x = 10^(1/2) or x = -10^(1/2)

x in { 10^(1/2), -10^(1/2) }